What are the solutions to the equation 4z^2-8z=0 ?

The solutions to the equation 4z^2-8z=0 are z=2,z=0

Find the zeros of 4z^2-8z=0

The zeros of 4z^2-8z=0 are z=2,z=0

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4 z^{2} - 8 z = 0

z = 2, z = 0

Solution steps

4 z^{2} - 8 z = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 \cdot 0 = 8

z_{1, 2} = \frac{- ( - 8 ) \pm 8}{2 \cdot 4}

Separate the solutions

z_{1} = \frac{- ( - 8 ) + 8}{2 \cdot 4}, z_{2} = \frac{- ( - 8 ) - 8}{2 \cdot 4}

z = \frac{- ( - 8 ) + 8}{2 \cdot 4} : 2

z = \frac{- ( - 8 ) - 8}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

z = 2, z = 0

2 x^{2} + 32 x = 0

3 s^{2} + 16 s + 12 = 0

5 (4 x - 3)^{2} - 4 (x - 9) (3 x + 5) = 9

x, x^{2} + y^{2} + z^{2} - 4 x + 6 y - 8 z = - 20

y^{2} - 14 y + 51 = 0

What are the solutions to the equation 4z^2-8z=0 ?
The solutions to the equation 4z^2-8z=0 are z=2,z=0
Find the zeros of 4z^2-8z=0
The zeros of 4z^2-8z=0 are z=2,z=0