What are the solutions to the equation 4x^2=-12x ?

The solutions to the equation 4x^2=-12x are x=0,x=-3

Find the zeros of 4x^2=-12x

The zeros of 4x^2=-12x are x=0,x=-3

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4 x^{2} = - 12 x

x = 0, x = - 3

Solution steps

4 x^{2} = - 12 x

Move

12 x

to the left side

4 x^{2} + 12 x = 0

Factor

4 x^{2} + 12 x : 4 x (x + 3)

4 x (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 3 = 0

Solve

x + 3 = 0 : x = - 3

The solutions to the quadratic equation are:

x = 0, x = - 3

x, x^{2} + 2 y^{2} + 3 z^{2} = 6

x^{1 + l o g_{x} (36)} = 6 x^{2}

x, x^{2} - \frac{23}{3} x + 14 = 0

5 x^{2} + 25 x + 30 = 0

\frac{3}{2} x^{2} - 6 x + 4

What are the solutions to the equation 4x^2=-12x ?
The solutions to the equation 4x^2=-12x are x=0,x=-3
Find the zeros of 4x^2=-12x
The zeros of 4x^2=-12x are x=0,x=-3