What are the solutions to the equation x^{1+log_{x}(36)}=6x^2 ?

The solutions to the equation x^{1+log_{x}(36)}=6x^2 are x=0,x=6

Find the zeros of x^{1+log_{x}(36)}=6x^2

The zeros of x^{1+log_{x}(36)}=6x^2 are x=0,x=6

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x^{1 + l o g_{x} (36)} = 6 x^{2}

x = 0, x = 6

Solution steps

x^{1 + l o g_{x} (36)} = 6 x^{2}

Move

6 x^{2}

to the left side

36 x - 6 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 6 x^{2} + 36 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 ( - 6 ) \cdot 0}{2 ( - 6 )}

3 6^{2} - 4 (- 6) \cdot 0 = 36

x_{1, 2} = \frac{- 36 \pm 36}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 36 + 36}{2 ( - 6 )}, x_{2} = \frac{- 36 - 36}{2 ( - 6 )}

x = \frac{- 36 + 36}{2 ( - 6 )} : 0

x = \frac{- 36 - 36}{2 ( - 6 )} : 6

The solutions to the quadratic equation are:

x = 0, x = 6

x, x^{2} - \frac{23}{3} x + 14 = 0

5 x^{2} + 25 x + 30 = 0

\frac{3}{2} x^{2} - 6 x + 4

- 4.9 t^{2} + 7.4 t + 1.55 = 0

2 x^{2} + 12 x + 1 = 0

What are the solutions to the equation x^{1+log_{x}(36)}=6x^2 ?
The solutions to the equation x^{1+log_{x}(36)}=6x^2 are x=0,x=6
Find the zeros of x^{1+log_{x}(36)}=6x^2
The zeros of x^{1+log_{x}(36)}=6x^2 are x=0,x=6