What are the solutions to the equation 2x^2+12x+1=0 ?

The solutions to the equation 2x^2+12x+1=0 are x=(-6+sqrt(34))/2 ,x=-(6+sqrt(34))/2

Find the zeros of 2x^2+12x+1=0

The zeros of 2x^2+12x+1=0 are x=(-6+sqrt(34))/2 ,x=-(6+sqrt(34))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 12 x + 1 = 0

x = \frac{- 6 + 34}{2}, x = - \frac{6 + 34}{2}

Decimal Notation

x = - 0.08452 \dots, x = - 5.91547 \dots

Solution steps

2 x^{2} + 12 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 2 \cdot 1}{2 \cdot 2}

1 2^{2} - 4 \cdot 2 \cdot 1 = 234

x_{1, 2} = \frac{- 12 \pm 2 34}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 12 + 2 34}{2 \cdot 2}, x_{2} = \frac{- 12 - 2 34}{2 \cdot 2}

x = \frac{- 12 + 2 34}{2 \cdot 2} : \frac{- 6 + 34}{2}

x = \frac{- 12 - 2 34}{2 \cdot 2} : - \frac{6 + 34}{2}

The solutions to the quadratic equation are:

x = \frac{- 6 + 34}{2}, x = - \frac{6 + 34}{2}

- 7 x^{2} + 7 x = 0

x^{2} = 0.8 x + 0.2

2 n^{2} = - 10 n - 5

n^{2} + 3 n - 12 = 6

x^{2} + 2 x - 2 = 0

What are the solutions to the equation 2x^2+12x+1=0 ?
The solutions to the equation 2x^2+12x+1=0 are x=(-6+sqrt(34))/2 ,x=-(6+sqrt(34))/2
Find the zeros of 2x^2+12x+1=0
The zeros of 2x^2+12x+1=0 are x=(-6+sqrt(34))/2 ,x=-(6+sqrt(34))/2