What are the solutions to the equation -7x^2+7x=0 ?

The solutions to the equation -7x^2+7x=0 are x=0,x=1

Find the zeros of -7x^2+7x=0

The zeros of -7x^2+7x=0 are x=0,x=1

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- 7 x^{2} + 7 x = 0

x = 0, x = 1

Solution steps

- 7 x^{2} + 7 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 7 ) \cdot 0}{2 ( - 7 )}

7^{2} - 4 (- 7) \cdot 0 = 7

x_{1, 2} = \frac{- 7 \pm 7}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- 7 + 7}{2 ( - 7 )}, x_{2} = \frac{- 7 - 7}{2 ( - 7 )}

x = \frac{- 7 + 7}{2 ( - 7 )} : 0

x = \frac{- 7 - 7}{2 ( - 7 )} : 1

The solutions to the quadratic equation are:

x = 0, x = 1

x^{2} = 0.8 x + 0.2

2 n^{2} = - 10 n - 5

n^{2} + 3 n - 12 = 6

x^{2} + 2 x - 2 = 0

0 = - x^{2} - 4 x + 4

What are the solutions to the equation -7x^2+7x=0 ?
The solutions to the equation -7x^2+7x=0 are x=0,x=1
Find the zeros of -7x^2+7x=0
The zeros of -7x^2+7x=0 are x=0,x=1