What are the solutions to the equation 13x^2-17x+7=0 ?

The solutions to the equation 13x^2-17x+7=0 are x= 17/26+i(5sqrt(3))/(26),x= 17/26-i(5sqrt(3))/(26)

Find the zeros of 13x^2-17x+7=0

The zeros of 13x^2-17x+7=0 are x= 17/26+i(5sqrt(3))/(26),x= 17/26-i(5sqrt(3))/(26)

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13 x^{2} - 17 x + 7 = 0

x = \frac{17}{26} + i \frac{5 3}{26}, x = \frac{17}{26} - i \frac{5 3}{26}

Solution steps

13 x^{2} - 17 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 13 \cdot 7}{2 \cdot 13}

Simplify

(- 17)^{2} - 4 \cdot 13 \cdot 7 : 53 i

x_{1, 2} = \frac{- ( - 17 ) \pm 5 3 i}{2 \cdot 13}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 5 3 i}{2 \cdot 13}, x_{2} = \frac{- ( - 17 ) - 5 3 i}{2 \cdot 13}

x = \frac{- ( - 17 ) + 5 3 i}{2 \cdot 13} : \frac{17}{26} + i \frac{5 3}{26}

x = \frac{- ( - 17 ) - 5 3 i}{2 \cdot 13} : \frac{17}{26} - i \frac{5 3}{26}

The solutions to the quadratic equation are:

x = \frac{17}{26} + i \frac{5 3}{26}, x = \frac{17}{26} - i \frac{5 3}{26}

\frac{x ^{2}}{9} - x + 2 = 0

x^{2} + π^{2} = 0

0 = \frac{1}{116} (3 x^{2} - 18 x + 24)

36 = x^{2} + 5 x

0 = 6 x - x^{2}

What are the solutions to the equation 13x^2-17x+7=0 ?
The solutions to the equation 13x^2-17x+7=0 are x= 17/26+i(5sqrt(3))/(26),x= 17/26-i(5sqrt(3))/(26)
Find the zeros of 13x^2-17x+7=0
The zeros of 13x^2-17x+7=0 are x= 17/26+i(5sqrt(3))/(26),x= 17/26-i(5sqrt(3))/(26)