What are the solutions to the equation (x^2)/9-x+2=0 ?

The solutions to the equation (x^2)/9-x+2=0 are x=6,x=3

Find the zeros of (x^2)/9-x+2=0

The zeros of (x^2)/9-x+2=0 are x=6,x=3

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\frac{x ^{2}}{9} - x + 2 = 0

x = 6, x = 3

Solution steps

\frac{x ^{2}}{9} - x + 2 = 0

Multiply both sides by

9

x^{2} - 9 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 18 = 3

x_{1, 2} = \frac{- ( - 9 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 3}{2 \cdot 1}

x = \frac{- ( - 9 ) + 3}{2 \cdot 1} : 6

x = \frac{- ( - 9 ) - 3}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 6, x = 3

x^{2} + π^{2} = 0

0 = \frac{1}{116} (3 x^{2} - 18 x + 24)

36 = x^{2} + 5 x

0 = 6 x - x^{2}

6^{2} - 4^{2} = x^{2}

What are the solutions to the equation (x^2)/9-x+2=0 ?
The solutions to the equation (x^2)/9-x+2=0 are x=6,x=3
Find the zeros of (x^2)/9-x+2=0
The zeros of (x^2)/9-x+2=0 are x=6,x=3