What are the solutions to the equation 6^2-4^2=x^2 ?

The solutions to the equation 6^2-4^2=x^2 are x=2sqrt(5),x=-2sqrt(5)

Find the zeros of 6^2-4^2=x^2

The zeros of 6^2-4^2=x^2 are x=2sqrt(5),x=-2sqrt(5)

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6^{2} - 4^{2} = x^{2}

x = 25, x = - 25

Decimal Notation

x = 4.47213 \dots, x = - 4.47213 \dots

Solution steps

6^{2} - 4^{2} = x^{2}

Switch sides

x^{2} = 6^{2} - 4^{2}

Simplify

6^{2} - 4^{2} : 20

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 20, x = - 20

20 = 25

- 20 = - 25

x = 25, x = - 25

5 x^{2} + 8 x + 4 = 4 x^{2} + 6 x + 3

X^{2} - X - 20 = 0

x + 2 = x^{2} - 1

5 x + 3 = - 2 x^{2}

x, 2 x^{2} + 5 y^{2} = 0

What are the solutions to the equation 6^2-4^2=x^2 ?
The solutions to the equation 6^2-4^2=x^2 are x=2sqrt(5),x=-2sqrt(5)
Find the zeros of 6^2-4^2=x^2
The zeros of 6^2-4^2=x^2 are x=2sqrt(5),x=-2sqrt(5)