What are the solutions to the equation 18m^2-27m-3=0 ?

The solutions to the equation 18m^2-27m-3=0 are m=(9+sqrt(105))/(12),m=(9-sqrt(105))/(12)

Find the zeros of 18m^2-27m-3=0

The zeros of 18m^2-27m-3=0 are m=(9+sqrt(105))/(12),m=(9-sqrt(105))/(12)

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18 m^{2} - 27 m - 3 = 0

m = \frac{9 + 105}{12}, m = \frac{9 - 105}{12}

Decimal Notation

m = 1.60391 \dots, m = - 0.10391 \dots

Solution steps

18 m^{2} - 27 m - 3 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 \cdot 18 ( - 3 )}{2 \cdot 18}

(- 27)^{2} - 4 \cdot 18 (- 3) = 3105

m_{1, 2} = \frac{- ( - 27 ) \pm 3 105}{2 \cdot 18}

Separate the solutions

m_{1} = \frac{- ( - 27 ) + 3 105}{2 \cdot 18}, m_{2} = \frac{- ( - 27 ) - 3 105}{2 \cdot 18}

m = \frac{- ( - 27 ) + 3 105}{2 \cdot 18} : \frac{9 + 105}{12}

m = \frac{- ( - 27 ) - 3 105}{2 \cdot 18} : \frac{9 - 105}{12}

The solutions to the quadratic equation are:

m = \frac{9 + 105}{12}, m = \frac{9 - 105}{12}

0.5 x^{2} - 1.61 x + 1.4 = 0

2 x^{2} - 10 x

x^{2} - 22 + 121 = 0

x, 3 x^{2} - 6 x - 1 = 0

1 = - 2 (x + 1)^{2} + 3

What are the solutions to the equation 18m^2-27m-3=0 ?
The solutions to the equation 18m^2-27m-3=0 are m=(9+sqrt(105))/(12),m=(9-sqrt(105))/(12)
Find the zeros of 18m^2-27m-3=0
The zeros of 18m^2-27m-3=0 are m=(9+sqrt(105))/(12),m=(9-sqrt(105))/(12)