What are the solutions to the equation solvefor x,3x^2-6x-1=0 ?

The solutions to the equation solvefor x,3x^2-6x-1=0 are x=(3+2sqrt(3))/3 ,x=(3-2sqrt(3))/3

Find the zeros of solvefor x,3x^2-6x-1=0

The zeros of solvefor x,3x^2-6x-1=0 are x=(3+2sqrt(3))/3 ,x=(3-2sqrt(3))/3

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x, 3 x^{2} - 6 x - 1 = 0

x = \frac{3 + 2 3}{3}, x = \frac{3 - 2 3}{3}

Decimal Notation

x = 2.15470 \dots, x = - 0.15470 \dots

Solution steps

3 x^{2} - 6 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 (- 1) = 43

x_{1, 2} = \frac{- ( - 6 ) \pm 4 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 4 3}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 4 3}{2 \cdot 3}

x = \frac{- ( - 6 ) + 4 3}{2 \cdot 3} : \frac{3 + 2 3}{3}

x = \frac{- ( - 6 ) - 4 3}{2 \cdot 3} : \frac{3 - 2 3}{3}

The solutions to the quadratic equation are:

x = \frac{3 + 2 3}{3}, x = \frac{3 - 2 3}{3}

1 = - 2 (x + 1)^{2} + 3

2 (x + \frac{1}{2})^{2} - \frac{9}{2} = 0

2 x^{2} + 7 x + 3 = 0

x^{2} - 2 x + 1 = - x^{2} + 3 x + 4

u, v^{2} = u^{2} - 2 a s

What are the solutions to the equation solvefor x,3x^2-6x-1=0 ?
The solutions to the equation solvefor x,3x^2-6x-1=0 are x=(3+2sqrt(3))/3 ,x=(3-2sqrt(3))/3
Find the zeros of solvefor x,3x^2-6x-1=0
The zeros of solvefor x,3x^2-6x-1=0 are x=(3+2sqrt(3))/3 ,x=(3-2sqrt(3))/3