What are the solutions to the equation 3x^2-2x=-6 ?

The solutions to the equation 3x^2-2x=-6 are x= 1/3+i(sqrt(17))/3 ,x= 1/3-i(sqrt(17))/3

Find the zeros of 3x^2-2x=-6

The zeros of 3x^2-2x=-6 are x= 1/3+i(sqrt(17))/3 ,x= 1/3-i(sqrt(17))/3

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3 x^{2} - 2 x = - 6

x = \frac{1}{3} + i \frac{17}{3}, x = \frac{1}{3} - i \frac{17}{3}

Solution steps

3 x^{2} - 2 x = - 6

Move

6

to the left side

3 x^{2} - 2 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 \cdot 6}{2 \cdot 3}

Simplify

(- 2)^{2} - 4 \cdot 3 \cdot 6 : 217 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 17 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 17 i}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 2 17 i}{2 \cdot 3}

x = \frac{- ( - 2 ) + 2 17 i}{2 \cdot 3} : \frac{1}{3} + i \frac{17}{3}

x = \frac{- ( - 2 ) - 2 17 i}{2 \cdot 3} : \frac{1}{3} - i \frac{17}{3}

The solutions to the quadratic equation are:

x = \frac{1}{3} + i \frac{17}{3}, x = \frac{1}{3} - i \frac{17}{3}

h^{2} = 7^{2} + 4^{2}

4 q^{2} + 3 q = 3 q^{2} - 2 q + 14

\frac{3 x ^{2} + 8 x + 8}{24} - \frac{x ( x - 3 )}{4} = x

4 u^{2} = 8 u

1 0^{2} + x^{2} = 1 4^{2}

What are the solutions to the equation 3x^2-2x=-6 ?
The solutions to the equation 3x^2-2x=-6 are x= 1/3+i(sqrt(17))/3 ,x= 1/3-i(sqrt(17))/3
Find the zeros of 3x^2-2x=-6
The zeros of 3x^2-2x=-6 are x= 1/3+i(sqrt(17))/3 ,x= 1/3-i(sqrt(17))/3