What are the solutions to the equation 3(x-2)+x^2-5(x+2)=7 ?

The solutions to the equation 3(x-2)+x^2-5(x+2)=7 are x=1+2sqrt(6),x=1-2sqrt(6)

Find the zeros of 3(x-2)+x^2-5(x+2)=7

The zeros of 3(x-2)+x^2-5(x+2)=7 are x=1+2sqrt(6),x=1-2sqrt(6)

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3 (x - 2) + x^{2} - 5 (x + 2) = 7

x = 1 + 26, x = 1 - 26

Decimal Notation

x = 5.89897 \dots, x = - 3.89897 \dots

Solution steps

3 (x - 2) + x^{2} - 5 (x + 2) = 7

Expand

3 (x - 2) + x^{2} - 5 (x + 2) : x^{2} - 2 x - 16

x^{2} - 2 x - 16 = 7

Move

7

to the left side

x^{2} - 2 x - 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 23 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 23) = 46

x_{1, 2} = \frac{- ( - 2 ) \pm 4 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4 6}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 4 6}{2 \cdot 1}

x = \frac{- ( - 2 ) + 4 6}{2 \cdot 1} : 1 + 26

x = \frac{- ( - 2 ) - 4 6}{2 \cdot 1} : 1 - 26

The solutions to the quadratic equation are:

x = 1 + 26, x = 1 - 26

4 x + (2 x + 7) = 3 x^{2} + 2 x + 5

(\frac{6 x - 16}{8})^{2} + x^{2} = 25

5801.51 = 10528 x^{2} - 22605 x + 13470

x^{2} + 107 x - 330 = 0

4 z (z - 3) = 0

What are the solutions to the equation 3(x-2)+x^2-5(x+2)=7 ?
The solutions to the equation 3(x-2)+x^2-5(x+2)=7 are x=1+2sqrt(6),x=1-2sqrt(6)
Find the zeros of 3(x-2)+x^2-5(x+2)=7
The zeros of 3(x-2)+x^2-5(x+2)=7 are x=1+2sqrt(6),x=1-2sqrt(6)