What are the solutions to the equation (5y+1)^2-2=16 ?

The solutions to the equation (5y+1)^2-2=16 are y=(3sqrt(2)-1)/5 ,y=(-3sqrt(2)-1)/5

Find the zeros of (5y+1)^2-2=16

The zeros of (5y+1)^2-2=16 are y=(3sqrt(2)-1)/5 ,y=(-3sqrt(2)-1)/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(5 y + 1)^{2} - 2 = 16

y = \frac{3 2 - 1}{5}, y = \frac{- 3 2 - 1}{5}

Decimal Notation

y = 0.64852 \dots, y = - 1.04852 \dots

Solution steps

(5 y + 1)^{2} - 2 = 16

Move

2

to the right side

(5 y + 1)^{2} = 18

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 y + 1 = 18 : y = \frac{3 2 - 1}{5}

Solve

5 y + 1 = - 18 : y = \frac{- 3 2 - 1}{5}

The solutions to the quadratic equation are:

y = \frac{3 2 - 1}{5}, y = \frac{- 3 2 - 1}{5}

5 x^{2} + 8 x + 80 = 0

4 y^{2} + 10 y - 5 = - y^{2} + 15 y + 5

B = (x + 8)^{2} + (x - 8)^{2} - (x + 2) (x - 2)

w^{2} = 8 w - 7

4 x = x^{2} - 6 x + 9

What are the solutions to the equation (5y+1)^2-2=16 ?
The solutions to the equation (5y+1)^2-2=16 are y=(3sqrt(2)-1)/5 ,y=(-3sqrt(2)-1)/5
Find the zeros of (5y+1)^2-2=16
The zeros of (5y+1)^2-2=16 are y=(3sqrt(2)-1)/5 ,y=(-3sqrt(2)-1)/5