What are the solutions to the equation 4x=x^2-6x+9 ?

The solutions to the equation 4x=x^2-6x+9 are x=9,x=1

Find the zeros of 4x=x^2-6x+9

The zeros of 4x=x^2-6x+9 are x=9,x=1

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4 x = x^{2} - 6 x + 9

x = 9, x = 1

Solution steps

4 x = x^{2} - 6 x + 9

Switch sides

x^{2} - 6 x + 9 = 4 x

Move

4 x

to the left side

x^{2} - 10 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 9 = 8

x_{1, 2} = \frac{- ( - 10 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 8}{2 \cdot 1}

x = \frac{- ( - 10 ) + 8}{2 \cdot 1} : 9

x = \frac{- ( - 10 ) - 8}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 9, x = 1

(x - 5)^{2} = - 17

\frac{( ( x + 6 ) \cdot x )}{2} = 176

5 x^{2} - 725 x + 12500 = 0

2 (x^{2} + 1) = 5 x

4 x^{2} - 2 x - 4 = 0

What are the solutions to the equation 4x=x^2-6x+9 ?
The solutions to the equation 4x=x^2-6x+9 are x=9,x=1
Find the zeros of 4x=x^2-6x+9
The zeros of 4x=x^2-6x+9 are x=9,x=1