What are the solutions to the equation 3x(x+1)-2=16 ?

The solutions to the equation 3x(x+1)-2=16 are x=2,x=-3

Find the zeros of 3x(x+1)-2=16

The zeros of 3x(x+1)-2=16 are x=2,x=-3

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3 x (x + 1) - 2 = 16

x = 2, x = - 3

Solution steps

3 x (x + 1) - 2 = 16

Expand

3 x (x + 1) - 2 : 3 x^{2} + 3 x - 2

3 x^{2} + 3 x - 2 = 16

Move

16

to the left side

3 x^{2} + 3 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 3 ( - 18 )}{2 \cdot 3}

3^{2} - 4 \cdot 3 (- 18) = 15

x_{1, 2} = \frac{- 3 \pm 15}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 3 + 15}{2 \cdot 3}, x_{2} = \frac{- 3 - 15}{2 \cdot 3}

x = \frac{- 3 + 15}{2 \cdot 3} : 2

x = \frac{- 3 - 15}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

x = 2, x = - 3

- 5 t^{2} + 14 t + 3 = 0

4 x^{2} - 11 x + 3 = 0

9 x^{2} + 12 x + 6 = 0

2 x^{2} + 5 x + 3 = 0

x, 9 x^{2} - 12 x y + 4 y^{2} + 38 x - 60 y + 121 = 0

What are the solutions to the equation 3x(x+1)-2=16 ?
The solutions to the equation 3x(x+1)-2=16 are x=2,x=-3
Find the zeros of 3x(x+1)-2=16
The zeros of 3x(x+1)-2=16 are x=2,x=-3