What are the solutions to the equation 2x(3x-1)=0 ?

The solutions to the equation 2x(3x-1)=0 are x=0,x= 1/3

Find the zeros of 2x(3x-1)=0

The zeros of 2x(3x-1)=0 are x=0,x= 1/3

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2 x (3 x - 1) = 0

x = 0, x = \frac{1}{3}

Solution steps

2 x (3 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 3 x - 1 = 0

Solve

3 x - 1 = 0 : x = \frac{1}{3}

The solutions to the quadratic equation are:

x = 0, x = \frac{1}{3}

5^{- \frac{1}{4}}

\frac{1}{2} - \frac{1}{2} x = - x^{2} + 2 x + 1

5 x^{2} - 30 = 0

(- \frac{1}{3})^{0}

\frac{1}{4} + \frac{3}{2} \cdot \frac{2}{3}

What are the solutions to the equation 2x(3x-1)=0 ?
The solutions to the equation 2x(3x-1)=0 are x=0,x= 1/3
Find the zeros of 2x(3x-1)=0
The zeros of 2x(3x-1)=0 are x=0,x= 1/3