What are the solutions to the equation p^2-7p=18 ?

The solutions to the equation p^2-7p=18 are p=9,p=-2

Find the zeros of p^2-7p=18

The zeros of p^2-7p=18 are p=9,p=-2

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p^{2} - 7 p = 18

p = 9, p = - 2

Solution steps

p^{2} - 7 p = 18

Move

18

to the left side

p^{2} - 7 p - 18 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 18) = 11

p_{1, 2} = \frac{- ( - 7 ) \pm 11}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 7 ) + 11}{2 \cdot 1}, p_{2} = \frac{- ( - 7 ) - 11}{2 \cdot 1}

p = \frac{- ( - 7 ) + 11}{2 \cdot 1} : 9

p = \frac{- ( - 7 ) - 11}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

p = 9, p = - 2

x, y = 2 x^{2} + 1

3 y = y^{2} - 4

7 x^{2} - 5 = 58

1 2^{2} + 5^{2} = r^{2}

18 - 27 x = - 4 x^{2}

What are the solutions to the equation p^2-7p=18 ?
The solutions to the equation p^2-7p=18 are p=9,p=-2
Find the zeros of p^2-7p=18
The zeros of p^2-7p=18 are p=9,p=-2