What are the solutions to the equation (x+2)^2=15 ?

The solutions to the equation (x+2)^2=15 are x=sqrt(15)-2,x=-sqrt(15)-2

Find the zeros of (x+2)^2=15

The zeros of (x+2)^2=15 are x=sqrt(15)-2,x=-sqrt(15)-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 2)^{2} = 15

x = 15 - 2, x = - 15 - 2

Decimal Notation

x = 1.87298 \dots, x = - 5.87298 \dots

Solution steps

(x + 2)^{2} = 15

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 15 : x = 15 - 2

Solve

x + 2 = - 15 : x = - 15 - 2

The solutions to the quadratic equation are:

x = 15 - 2, x = - 15 - 2

4 x^{2} + 20 x + 8 = 0

0 = - 27 x^{2} + 1890 x + 9831

(- \frac{5}{3})^{2} + y^{2} = 1

- x^{2} + 4 x - 20

x, x^{2} + y^{2} - 2 x - 6 y + 10 = 0

What are the solutions to the equation (x+2)^2=15 ?
The solutions to the equation (x+2)^2=15 are x=sqrt(15)-2,x=-sqrt(15)-2
Find the zeros of (x+2)^2=15
The zeros of (x+2)^2=15 are x=sqrt(15)-2,x=-sqrt(15)-2