What are the solutions to the equation 5v^2+4=-9v ?

The solutions to the equation 5v^2+4=-9v are v=-4/5 ,v=-1

Find the zeros of 5v^2+4=-9v

The zeros of 5v^2+4=-9v are v=-4/5 ,v=-1

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5 v^{2} + 4 = - 9 v

v = - \frac{4}{5}, v = - 1

Decimal Notation

v = - 0.8, v = - 1

Solution steps

5 v^{2} + 4 = - 9 v

Move

9 v

to the left side

5 v^{2} + 4 + 9 v = 0

Write in the standard form

a x^{2} + b x + c = 0

5 v^{2} + 9 v + 4 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

9^{2} - 4 \cdot 5 \cdot 4 = 1

v_{1, 2} = \frac{- 9 \pm 1}{2 \cdot 5}

Separate the solutions

v_{1} = \frac{- 9 + 1}{2 \cdot 5}, v_{2} = \frac{- 9 - 1}{2 \cdot 5}

v = \frac{- 9 + 1}{2 \cdot 5} : - \frac{4}{5}

v = \frac{- 9 - 1}{2 \cdot 5} : - 1

The solutions to the quadratic equation are:

v = - \frac{4}{5}, v = - 1

x, f = (m - 2) x^{2} + (n - 1) x + (p - 3)

x^{2} + 10 x - 375 = 0

x, 6 x^{2} y + 11 x y - 2 x = 10 y

4 w^{2} + 8 w + 4 = 0

y^{2} - 13 y + 40 = 0

What are the solutions to the equation 5v^2+4=-9v ?
The solutions to the equation 5v^2+4=-9v are v=-4/5 ,v=-1
Find the zeros of 5v^2+4=-9v
The zeros of 5v^2+4=-9v are v=-4/5 ,v=-1