What are the solutions to the equation 4w^2+8w+4=0 ?

The solutions to the equation 4w^2+8w+4=0 are w=-1

Find the zeros of 4w^2+8w+4=0

The zeros of 4w^2+8w+4=0 are w=-1

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4 w^{2} + 8 w + 4 = 0

w = - 1

Solution steps

4 w^{2} + 8 w + 4 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 \cdot 4}{2 \cdot 4}

8^{2} - 4 \cdot 4 \cdot 4 = 0

w_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 4}

w = \frac{- 8}{2 \cdot 4}

\frac{- 8}{2 \cdot 4} = - 1

w = - 1

The solution to the quadratic equation is:

w = - 1

y^{2} - 13 y + 40 = 0

x^{2} + 2 (x + 1) = 5

q^{2} = 40000000 \cdot 10

x^{2} - 12 x + 196 = 0

5 x^{2} - 12 x - 27 = 0

What are the solutions to the equation 4w^2+8w+4=0 ?
The solutions to the equation 4w^2+8w+4=0 are w=-1
Find the zeros of 4w^2+8w+4=0
The zeros of 4w^2+8w+4=0 are w=-1