What are the solutions to the equation 5x^2-12x-27=0 ?

The solutions to the equation 5x^2-12x-27=0 are x=(3(2+sqrt(19)))/5 ,x=(3(2-sqrt(19)))/5

Find the zeros of 5x^2-12x-27=0

The zeros of 5x^2-12x-27=0 are x=(3(2+sqrt(19)))/5 ,x=(3(2-sqrt(19)))/5

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5 x^{2} - 12 x - 27 = 0

x = \frac{3 ( 2 + 19 )}{5}, x = \frac{3 ( 2 - 19 )}{5}

Decimal

x = 3.81533 \dots, x = - 1.41533 \dots

Solution steps

5 x^{2} - 12 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 5 ( - 27 )}{2 \cdot 5}

(- 12)^{2} - 4 \cdot 5 (- 27) = 619

x_{1, 2} = \frac{- ( - 12 ) \pm 6 19}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6 19}{2 \cdot 5}, x_{2} = \frac{- ( - 12 ) - 6 19}{2 \cdot 5}

x = \frac{- ( - 12 ) + 6 19}{2 \cdot 5} : \frac{3 ( 2 + 19 )}{5}

x = \frac{- ( - 12 ) - 6 19}{2 \cdot 5} : \frac{3 ( 2 - 19 )}{5}

The solutions to the quadratic equation are:

x = \frac{3 ( 2 + 19 )}{5}, x = \frac{3 ( 2 - 19 )}{5}

4 (x + 8)^{2} = 28

x, (λ^{2} - 9) x^{2} + (λ^{2} - 16) y^{2} = λ

- 5 m^{2} - 5 m - 56 = 0

3 x + x^{2} = 0

(x - 5)^{2} = 32

What are the solutions to the equation 5x^2-12x-27=0 ?
The solutions to the equation 5x^2-12x-27=0 are x=(3(2+sqrt(19)))/5 ,x=(3(2-sqrt(19)))/5
Find the zeros of 5x^2-12x-27=0
The zeros of 5x^2-12x-27=0 are x=(3(2+sqrt(19)))/5 ,x=(3(2-sqrt(19)))/5