What are the solutions to the equation -6x^2+36x-42=0 ?

The solutions to the equation -6x^2+36x-42=0 are x=3-sqrt(2),x=3+sqrt(2)

Find the zeros of -6x^2+36x-42=0

The zeros of -6x^2+36x-42=0 are x=3-sqrt(2),x=3+sqrt(2)

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- 6 x^{2} + 36 x - 42 = 0

x = 3 - 2, x = 3 + 2

Solution steps

- 6 x^{2} + 36 x - 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 ( - 6 ) ( - 42 )}{2 ( - 6 )}

3 6^{2} - 4 (- 6) (- 42) = 122

x_{1, 2} = \frac{- 36 \pm 12 2}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 36 + 12 2}{2 ( - 6 )}, x_{2} = \frac{- 36 - 12 2}{2 ( - 6 )}

x = \frac{- 36 + 12 2}{2 ( - 6 )} : 3 - 2

x = \frac{- 36 - 12 2}{2 ( - 6 )} : 3 + 2

The solutions to the quadratic equation are:

x = 3 - 2, x = 3 + 2

x^{2} = 64

9 x^{2} + 6 x + 1 = 0

2 h - 8 = h + 17

4 - 4

\frac{48 x ^{3}}{3 x y ^{2}}

What are the solutions to the equation -6x^2+36x-42=0 ?
The solutions to the equation -6x^2+36x-42=0 are x=3-sqrt(2),x=3+sqrt(2)
Find the zeros of -6x^2+36x-42=0
The zeros of -6x^2+36x-42=0 are x=3-sqrt(2),x=3+sqrt(2)