What are the solutions to the equation 2a^2-17a+8=0 ?

The solutions to the equation 2a^2-17a+8=0 are a=8,a= 1/2

Find the zeros of 2a^2-17a+8=0

The zeros of 2a^2-17a+8=0 are a=8,a= 1/2

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2 a^{2} - 17 a + 8 = 0

a = 8, a = \frac{1}{2}

Decimal Notation

a = 8, a = 0.5

Solution steps

2 a^{2} - 17 a + 8 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 2 \cdot 8}{2 \cdot 2}

(- 17)^{2} - 4 \cdot 2 \cdot 8 = 15

a_{1, 2} = \frac{- ( - 17 ) \pm 15}{2 \cdot 2}

Separate the solutions

a_{1} = \frac{- ( - 17 ) + 15}{2 \cdot 2}, a_{2} = \frac{- ( - 17 ) - 15}{2 \cdot 2}

a = \frac{- ( - 17 ) + 15}{2 \cdot 2} : 8

a = \frac{- ( - 17 ) - 15}{2 \cdot 2} : \frac{1}{2}

The solutions to the quadratic equation are:

a = 8, a = \frac{1}{2}

9 x^{2} - x = 4 x + 7 x^{2}

(x + 5)^{2} = (x + 1)^{2} + (2 x)^{2}

3 x^{2} + 7 x + 8 = 0

y^{2} + 6 y + 3 = 0

6.5 - 2.5 x^{2} = 0

What are the solutions to the equation 2a^2-17a+8=0 ?
The solutions to the equation 2a^2-17a+8=0 are a=8,a= 1/2
Find the zeros of 2a^2-17a+8=0
The zeros of 2a^2-17a+8=0 are a=8,a= 1/2