What are the solutions to the equation 9x^2-x=4x+7x^2 ?

The solutions to the equation 9x^2-x=4x+7x^2 are x= 5/2 ,x=0

Find the zeros of 9x^2-x=4x+7x^2

The zeros of 9x^2-x=4x+7x^2 are x= 5/2 ,x=0

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9 x^{2} - x = 4 x + 7 x^{2}

x = \frac{5}{2}, x = 0

Decimal Notation

x = 2.5, x = 0

Solution steps

9 x^{2} - x = 4 x + 7 x^{2}

Move

7 x^{2}

to the left side

2 x^{2} - x = 4 x

Move

4 x

to the left side

2 x^{2} - 5 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 \cdot 0 = 5

x_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 2}

x = \frac{- ( - 5 ) + 5}{2 \cdot 2} : \frac{5}{2}

x = \frac{- ( - 5 ) - 5}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = 0

(x + 5)^{2} = (x + 1)^{2} + (2 x)^{2}

3 x^{2} + 7 x + 8 = 0

y^{2} + 6 y + 3 = 0

6.5 - 2.5 x^{2} = 0

(x - 1) (x + 3) = 5 (x - 1)

What are the solutions to the equation 9x^2-x=4x+7x^2 ?
The solutions to the equation 9x^2-x=4x+7x^2 are x= 5/2 ,x=0
Find the zeros of 9x^2-x=4x+7x^2
The zeros of 9x^2-x=4x+7x^2 are x= 5/2 ,x=0