What are the solutions to the equation (x-1)(x+3)=5(x-1) ?

The solutions to the equation (x-1)(x+3)=5(x-1) are x=1,x=2

Find the zeros of (x-1)(x+3)=5(x-1)

The zeros of (x-1)(x+3)=5(x-1) are x=1,x=2

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(x - 1) (x + 3) = 5 (x - 1)

x = 1, x = 2

Solution steps

(x - 1) (x + 3) = 5 (x - 1)

Move

5 (x - 1)

to the left side

(x - 1) (x + 3) - 5 (x - 1) = 0

Factor

(x - 1) (x + 3) - 5 (x - 1) : (x - 1) (x - 2)

(x - 1) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x - 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 2 = 0 : x = 2

The solutions to the quadratic equation are:

x = 1, x = 2

2 x^{2} + 17 x + 8 = 0

5 x^{2} - 9 = 11

x^{2} + 5 = 6

- λ^{2} - 2 λ - 3 = 0

2 x^{2} = 1 - x

What are the solutions to the equation (x-1)(x+3)=5(x-1) ?
The solutions to the equation (x-1)(x+3)=5(x-1) are x=1,x=2
Find the zeros of (x-1)(x+3)=5(x-1)
The zeros of (x-1)(x+3)=5(x-1) are x=1,x=2