What are the solutions to the equation (2x^2-9x)2+4(x^2-9x)-45=0 ?

The solutions to the equation (2x^2-9x)2+4(x^2-9x)-45=0 are x= 15/2 ,x=-3/4

Find the zeros of (2x^2-9x)2+4(x^2-9x)-45=0

The zeros of (2x^2-9x)2+4(x^2-9x)-45=0 are x= 15/2 ,x=-3/4

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(2 x^{2} - 9 x) 2 + 4 (x^{2} - 9 x) - 45 = 0

x = \frac{15}{2}, x = - \frac{3}{4}

Decimal Notation

x = 7.5, x = - 0.75

Solution steps

(2 x^{2} - 9 x) \cdot 2 + 4 (x^{2} - 9 x) - 45 = 0

Expand

(2 x^{2} - 9 x) \cdot 2 + 4 (x^{2} - 9 x) - 45 : 8 x^{2} - 54 x - 45

8 x^{2} - 54 x - 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 54 ) \pm ( - 54 ) ^{2} - 4 \cdot 8 ( - 45 )}{2 \cdot 8}

(- 54)^{2} - 4 \cdot 8 (- 45) = 66

x_{1, 2} = \frac{- ( - 54 ) \pm 66}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 54 ) + 66}{2 \cdot 8}, x_{2} = \frac{- ( - 54 ) - 66}{2 \cdot 8}

x = \frac{- ( - 54 ) + 66}{2 \cdot 8} : \frac{15}{2}

x = \frac{- ( - 54 ) - 66}{2 \cdot 8} : - \frac{3}{4}

The solutions to the quadratic equation are:

x = \frac{15}{2}, x = - \frac{3}{4}

(s + 3)^{2} = 0

x, x^{2} + 12 x - 28 = 0

x^{2} - 12 x + 46 = 0

75 = - \frac{1}{4} x^{2} + 5 x

2 w^{2} - w - 21 = 0

What are the solutions to the equation (2x^2-9x)2+4(x^2-9x)-45=0 ?
The solutions to the equation (2x^2-9x)2+4(x^2-9x)-45=0 are x= 15/2 ,x=-3/4
Find the zeros of (2x^2-9x)2+4(x^2-9x)-45=0
The zeros of (2x^2-9x)2+4(x^2-9x)-45=0 are x= 15/2 ,x=-3/4