What are the solutions to the equation x^2-12x+46=0 ?

The solutions to the equation x^2-12x+46=0 are x=6+sqrt(10)i,x=6-sqrt(10)i

Find the zeros of x^2-12x+46=0

The zeros of x^2-12x+46=0 are x=6+sqrt(10)i,x=6-sqrt(10)i

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x^{2} - 12 x + 46 = 0

x = 6 + 10 i, x = 6 - 10 i

Solution steps

x^{2} - 12 x + 46 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 46}{2 \cdot 1}

Simplify

(- 12)^{2} - 4 \cdot 1 \cdot 46 : 210 i

x_{1, 2} = \frac{- ( - 12 ) \pm 2 10 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 10 i}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2 10 i}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2 10 i}{2 \cdot 1} : 6 + 10 i

x = \frac{- ( - 12 ) - 2 10 i}{2 \cdot 1} : 6 - 10 i

The solutions to the quadratic equation are:

x = 6 + 10 i, x = 6 - 10 i

75 = - \frac{1}{4} x^{2} + 5 x

2 w^{2} - w - 21 = 0

n^{2} - 6 n + 7 = 0

(300 + 10 x) (1.6 - 0.01 x)

5 x^{2} - 8 x + 16 = 0

What are the solutions to the equation x^2-12x+46=0 ?
The solutions to the equation x^2-12x+46=0 are x=6+sqrt(10)i,x=6-sqrt(10)i
Find the zeros of x^2-12x+46=0
The zeros of x^2-12x+46=0 are x=6+sqrt(10)i,x=6-sqrt(10)i