What are the solutions to the equation n^2-6n+7=0 ?

The solutions to the equation n^2-6n+7=0 are n=3+sqrt(2),n=3-sqrt(2)

Find the zeros of n^2-6n+7=0

The zeros of n^2-6n+7=0 are n=3+sqrt(2),n=3-sqrt(2)

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n^{2} - 6 n + 7 = 0

n = 3 + 2, n = 3 - 2

Decimal Notation

n = 4.41421 \dots, n = 1.58578 \dots

Solution steps

n^{2} - 6 n + 7 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 7 = 22

n_{1, 2} = \frac{- ( - 6 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 6 ) + 2 2}{2 \cdot 1}, n_{2} = \frac{- ( - 6 ) - 2 2}{2 \cdot 1}

n = \frac{- ( - 6 ) + 2 2}{2 \cdot 1} : 3 + 2

n = \frac{- ( - 6 ) - 2 2}{2 \cdot 1} : 3 - 2

The solutions to the quadratic equation are:

n = 3 + 2, n = 3 - 2

(300 + 10 x) (1.6 - 0.01 x)

5 x^{2} - 8 x + 16 = 0

\frac{1}{5} k (k + 4) = 0.5

w^{2} + 4 w = 0

x^{2} - 2 = 8

What are the solutions to the equation n^2-6n+7=0 ?
The solutions to the equation n^2-6n+7=0 are n=3+sqrt(2),n=3-sqrt(2)
Find the zeros of n^2-6n+7=0
The zeros of n^2-6n+7=0 are n=3+sqrt(2),n=3-sqrt(2)