What are the solutions to the equation w^2+4w=0 ?

The solutions to the equation w^2+4w=0 are w=0,w=-4

Find the zeros of w^2+4w=0

The zeros of w^2+4w=0 are w=0,w=-4

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w^{2} + 4 w = 0

w = 0, w = - 4

Solution steps

w^{2} + 4 w = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 0 = 4

w_{1, 2} = \frac{- 4 \pm 4}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 4 + 4}{2 \cdot 1}, w_{2} = \frac{- 4 - 4}{2 \cdot 1}

w = \frac{- 4 + 4}{2 \cdot 1} : 0

w = \frac{- 4 - 4}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

w = 0, w = - 4

x^{2} - 2 = 8

x^{2} + x - 56 = 0

z, x^{2} + y^{2} = z^{2}

(r^{2} + r + 1) = 0

10 p^{2} + 2.5 (1 - p^{2}) = 2.5 p^{2} + 5 (1 - p^{2})

What are the solutions to the equation w^2+4w=0 ?
The solutions to the equation w^2+4w=0 are w=0,w=-4
Find the zeros of w^2+4w=0
The zeros of w^2+4w=0 are w=0,w=-4