What are the solutions to the equation 10p^2+2.5(1-p^2)=2.5p^2+5(1-p^2) ?

The solutions to the equation 10p^2+2.5(1-p^2)=2.5p^2+5(1-p^2) are p= 1/2 ,p=-1/2

Find the zeros of 10p^2+2.5(1-p^2)=2.5p^2+5(1-p^2)

The zeros of 10p^2+2.5(1-p^2)=2.5p^2+5(1-p^2) are p= 1/2 ,p=-1/2

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10 p^{2} + 2.5 (1 - p^{2}) = 2.5 p^{2} + 5 (1 - p^{2})

p = \frac{1}{2}, p = - \frac{1}{2}

Decimal Notation

p = 0.5, p = - 0.5

Solution steps

10 p^{2} + 2.5 (1 - p^{2}) = 2.5 p^{2} + 5 (1 - p^{2})

Expand

10 p^{2} + 2.5 (1 - p^{2}) : 7.5 p^{2} + 2.5

Expand

2.5 p^{2} + 5 (1 - p^{2}) : - 2.5 p^{2} + 5

7.5 p^{2} + 2.5 = - 2.5 p^{2} + 5

Move

2.5

to the right side

7.5 p^{2} = - 2.5 p^{2} + 2.5

Move

2.5 p^{2}

to the left side

10 p^{2} = 2.5

Divide both sides by

10

p^{2} = 0.25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = 0.25, p = - 0.25

0.25 = \frac{1}{2}

- 0.25 = - \frac{1}{2}

p = \frac{1}{2}, p = - \frac{1}{2}

x, x^{2} + 16 = 0

p^{2} + p - 42 = 0

(- x^{2} - 1) = 0

9 x^{2} - 6 x + 2

m^{2} + 10 m - 17 = 0

What are the solutions to the equation 10p^2+2.5(1-p^2)=2.5p^2+5(1-p^2) ?
The solutions to the equation 10p^2+2.5(1-p^2)=2.5p^2+5(1-p^2) are p= 1/2 ,p=-1/2
Find the zeros of 10p^2+2.5(1-p^2)=2.5p^2+5(1-p^2)
The zeros of 10p^2+2.5(1-p^2)=2.5p^2+5(1-p^2) are p= 1/2 ,p=-1/2