What are the solutions to the equation (-x^2-1)=0 ?

The solutions to the equation (-x^2-1)=0 are x=i,x=-i

Find the zeros of (-x^2-1)=0

The zeros of (-x^2-1)=0 are x=i,x=-i

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(- x^{2} - 1) = 0

x = i, x = - i

Solution steps

(- x^{2} - 1) = 0

- x^{2} - 1 = 0

Move

1

to the right side

- x^{2} = 1

Divide both sides by

- 1

x^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 1, x = - - 1

- 1 = i

- - 1 = - i

x = i, x = - i

9 x^{2} - 6 x + 2

m^{2} + 10 m - 17 = 0

2 x^{2} - 44 x + 224 = 0

x^{2} - 8 x - 1 = 0

t, s t + t = t^{2} + s

What are the solutions to the equation (-x^2-1)=0 ?
The solutions to the equation (-x^2-1)=0 are x=i,x=-i
Find the zeros of (-x^2-1)=0
The zeros of (-x^2-1)=0 are x=i,x=-i