What are the solutions to the equation completesquare x^2-8x-1=0 ?

The solutions to the equation completesquare x^2-8x-1=0 are x=sqrt(17)+4,x=-sqrt(17)+4

Find the zeros of completesquare x^2-8x-1=0

The zeros of completesquare x^2-8x-1=0 are x=sqrt(17)+4,x=-sqrt(17)+4

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x^{2} - 8 x - 1 = 0

x = 17 + 4, x = - 17 + 4

Decimal Notation

x = 8.12310 \dots, x = - 0.12310 \dots

Solution steps

x^{2} - 8 x - 1 = 0

Move

1

to the right side

x^{2} - 8 x = 1

Rewrite in the form

(x + a)^{2} = b

(x - 4)^{2} = 17

For

the solutions are

f (x) = a, - a

Solve

x - 4 = 17 : x = 17 + 4

Solve

x - 4 = - 17 : x = - 17 + 4

The solutions to the quadratic equation are:

x = 17 + 4, x = - 17 + 4

t, s t + t = t^{2} + s

y^{2} - 18 y + 45 = 0

x^{2} - 7 x + 3 = 50

1.81 L^{2} + 22.275 L - 750 = 0

x^{2} = \frac{- 5}{2}

What are the solutions to the equation completesquare x^2-8x-1=0 ?
The solutions to the equation completesquare x^2-8x-1=0 are x=sqrt(17)+4,x=-sqrt(17)+4
Find the zeros of completesquare x^2-8x-1=0
The zeros of completesquare x^2-8x-1=0 are x=sqrt(17)+4,x=-sqrt(17)+4