What are the solutions to the equation x^2=(-5)/2 ?

The solutions to the equation x^2=(-5)/2 are x=sqrt(5/2)i,x=-sqrt(5/2)i

Find the zeros of x^2=(-5)/2

The zeros of x^2=(-5)/2 are x=sqrt(5/2)i,x=-sqrt(5/2)i

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x^{2} = \frac{- 5}{2}

x = \frac{5}{2} i, x = - \frac{5}{2} i

Solution steps

x^{2} = \frac{- 5}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

x^{2} = - \frac{5}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{5}{2}, x = - - \frac{5}{2}

- \frac{5}{2} = \frac{5}{2} i

- - \frac{5}{2} = - \frac{5}{2} i

x = \frac{5}{2} i, x = - \frac{5}{2} i

d^{2} - 1 = 0

2 x^{2} - 10 x + 2 = 0

x, x^{2} - 3 k x + 9 = 0

x, 3 x^{2} + 2 m x - 9 = 0

x, x^{2} + 3 x y + y^{2} = 1

What are the solutions to the equation x^2=(-5)/2 ?
The solutions to the equation x^2=(-5)/2 are x=sqrt(5/2)i,x=-sqrt(5/2)i
Find the zeros of x^2=(-5)/2
The zeros of x^2=(-5)/2 are x=sqrt(5/2)i,x=-sqrt(5/2)i