What are the solutions to the equation solvefor x,x^2+5x-(p^2+p-6)=0 ?

The solutions to the equation solvefor x,x^2+5x-(p^2+p-6)=0 are x=p-2,x=-p-3

Find the zeros of solvefor x,x^2+5x-(p^2+p-6)=0

The zeros of solvefor x,x^2+5x-(p^2+p-6)=0 are x=p-2,x=-p-3

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solve for

x, x^{2} + 5 x - (p^{2} + p - 6) = 0

x = p - 2, x = - p - 3

Solution steps

x^{2} + 5 x - (p^{2} + p - 6) = 0

Expand

x^{2} + 5 x - (p^{2} + p - 6) : x^{2} + 5 x - p^{2} - p + 6

x^{2} + 5 x - p^{2} - p + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - p ^{2} - p + 6 )}{2 \cdot 1}

Simplify

5^{2} - 4 \cdot 1 \cdot (- p^{2} - p + 6) : 2 p + 1

x_{1, 2} = \frac{- 5 \pm ( 2 p + 1 )}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 2 p + 1}{2 \cdot 1}, x_{2} = \frac{- 5 - ( 2 p + 1 )}{2 \cdot 1}

x = \frac{- 5 + 2 p + 1}{2 \cdot 1} : p - 2

x = \frac{- 5 - ( 2 p + 1 )}{2 \cdot 1} : - p - 3

The solutions to the quadratic equation are:

x = p - 2, x = - p - 3

- 17 - 8 x^{2} = 4 x - 3 x^{2}

- x^{2} - 9 x + 22 = 0

- 0.2 (q - 25)^{2} + 165 = - 2 q + 140

x, x^{2} + y^{3} = 3 x y + 2

x - 6 = (x - 2) (x + 3)

What are the solutions to the equation solvefor x,x^2+5x-(p^2+p-6)=0 ?
The solutions to the equation solvefor x,x^2+5x-(p^2+p-6)=0 are x=p-2,x=-p-3
Find the zeros of solvefor x,x^2+5x-(p^2+p-6)=0
The zeros of solvefor x,x^2+5x-(p^2+p-6)=0 are x=p-2,x=-p-3