What are the solutions to the equation -0.2(q-25)^2+165=-2q+140 ?

The solutions to the equation -0.2(q-25)^2+165=-2q+140 are q=10,q=50

Find the zeros of -0.2(q-25)^2+165=-2q+140

The zeros of -0.2(q-25)^2+165=-2q+140 are q=10,q=50

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- 0.2 (q - 25)^{2} + 165 = - 2 q + 140

q = 10, q = 50

Solution steps

- 0.2 (q - 25)^{2} + 165 = - 2 q + 140

Multiply both sides by

10

- 2 (q - 25)^{2} + 1650 = - 20 q + 1400

Expand

- 2 (q - 25)^{2} + 1650 : - 2 q^{2} + 100 q + 400

- 2 q^{2} + 100 q + 400 = - 20 q + 1400

Move

1400

to the left side

- 2 q^{2} + 100 q - 1000 = - 20 q

Move

20 q

to the left side

- 2 q^{2} + 120 q - 1000 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 120 \pm 12 0 ^{2} - 4 ( - 2 ) ( - 1000 )}{2 ( - 2 )}

12 0^{2} - 4 (- 2) (- 1000) = 80

q_{1, 2} = \frac{- 120 \pm 80}{2 ( - 2 )}

Separate the solutions

q_{1} = \frac{- 120 + 80}{2 ( - 2 )}, q_{2} = \frac{- 120 - 80}{2 ( - 2 )}

q = \frac{- 120 + 80}{2 ( - 2 )} : 10

q = \frac{- 120 - 80}{2 ( - 2 )} : 50

The solutions to the quadratic equation are:

q = 10, q = 50

x, x^{2} + y^{3} = 3 x y + 2

x - 6 = (x - 2) (x + 3)

(3 x - 5) (x + 3) = 0

4200 = x^{2} - 160 x + 10000

2 A^{2} - 3 A = 0

What are the solutions to the equation -0.2(q-25)^2+165=-2q+140 ?
The solutions to the equation -0.2(q-25)^2+165=-2q+140 are q=10,q=50
Find the zeros of -0.2(q-25)^2+165=-2q+140
The zeros of -0.2(q-25)^2+165=-2q+140 are q=10,q=50