What are the solutions to the equation 4200=x^2-160x+10000 ?

The solutions to the equation 4200=x^2-160x+10000 are x=10(8+sqrt(6)),x=10(8-sqrt(6))

Find the zeros of 4200=x^2-160x+10000

The zeros of 4200=x^2-160x+10000 are x=10(8+sqrt(6)),x=10(8-sqrt(6))

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4200 = x^{2} - 160 x + 10000

x = 10 (8 + 6), x = 10 (8 - 6)

Decimal Notation

x = 104.49489 \dots, x = 55.50510 \dots

Solution steps

4200 = x^{2} - 160 x + 10000

Switch sides

x^{2} - 160 x + 10000 = 4200

Move

4200

to the left side

x^{2} - 160 x + 5800 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 160 ) \pm ( - 160 ) ^{2} - 4 \cdot 1 \cdot 5800}{2 \cdot 1}

(- 160)^{2} - 4 \cdot 1 \cdot 5800 = 206

x_{1, 2} = \frac{- ( - 160 ) \pm 20 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 160 ) + 20 6}{2 \cdot 1}, x_{2} = \frac{- ( - 160 ) - 20 6}{2 \cdot 1}

x = \frac{- ( - 160 ) + 20 6}{2 \cdot 1} : 10 (8 + 6)

x = \frac{- ( - 160 ) - 20 6}{2 \cdot 1} : 10 (8 - 6)

The solutions to the quadratic equation are:

x = 10 (8 + 6), x = 10 (8 - 6)

2 A^{2} - 3 A = 0

4 x^{2} + 6 x - 24 = 0

x^{2} + 4 x - 72 = 0

x^{2} - \frac{1}{3} x - \frac{4}{9} = 0

16 x^{2} - 24 x + 5 = 0

What are the solutions to the equation 4200=x^2-160x+10000 ?
The solutions to the equation 4200=x^2-160x+10000 are x=10(8+sqrt(6)),x=10(8-sqrt(6))
Find the zeros of 4200=x^2-160x+10000
The zeros of 4200=x^2-160x+10000 are x=10(8+sqrt(6)),x=10(8-sqrt(6))