What are the solutions to the equation 2x^{(2)}+5x-2=0 ?

The solutions to the equation 2x^{(2)}+5x-2=0 are x=(-5+sqrt(41))/4 ,x=(-5-sqrt(41))/4

Find the zeros of 2x^{(2)}+5x-2=0

The zeros of 2x^{(2)}+5x-2=0 are x=(-5+sqrt(41))/4 ,x=(-5-sqrt(41))/4

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2 x^{(2)} + 5 x - 2 = 0

x = \frac{- 5 + 41}{4}, x = \frac{- 5 - 41}{4}

Decimal Notation

x = 0.35078 \dots, x = - 2.85078 \dots

Solution steps

2 x^{(2)} + 5 x - 2 = 0

Refine

2 x^{2} + 5 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 2 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 2) = 41

x_{1, 2} = \frac{- 5 \pm 41}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 41}{2 \cdot 2}, x_{2} = \frac{- 5 - 41}{2 \cdot 2}

x = \frac{- 5 + 41}{2 \cdot 2} : \frac{- 5 + 41}{4}

x = \frac{- 5 - 41}{2 \cdot 2} : \frac{- 5 - 41}{4}

The solutions to the quadratic equation are:

x = \frac{- 5 + 41}{4}, x = \frac{- 5 - 41}{4}

x, s (x) = - 2 x^{2} - 12 x - 17

10 - 6 (8 x - 2) = 9 x (3 + 4 x)

x, x^{2} + y^{2} + z^{6} = 1

(x - 1)^{2} = 3 x - 5

20.03 = 22.4 \cdot 1000 x (\frac{0.113 - x}{2})

What are the solutions to the equation 2x^{(2)}+5x-2=0 ?
The solutions to the equation 2x^{(2)}+5x-2=0 are x=(-5+sqrt(41))/4 ,x=(-5-sqrt(41))/4
Find the zeros of 2x^{(2)}+5x-2=0
The zeros of 2x^{(2)}+5x-2=0 are x=(-5+sqrt(41))/4 ,x=(-5-sqrt(41))/4