What are the solutions to the equation x-3-(-x(x+1)+4)-5=(-x+6) ?

The solutions to the equation x-3-(-x(x+1)+4)-5=(-x+6) are x=3,x=-6

Find the zeros of x-3-(-x(x+1)+4)-5=(-x+6)

The zeros of x-3-(-x(x+1)+4)-5=(-x+6) are x=3,x=-6

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x - 3 - (- x (x + 1) + 4) - 5 = (- x + 6)

x = 3, x = - 6

Solution steps

x - 3 - (- x (x + 1) + 4) - 5 = (- x + 6)

Expand

x - 3 - (- x (x + 1) + 4) - 5 : x^{2} + 2 x - 12

x^{2} + 2 x - 12 = - x + 6

Move

6

to the left side

x^{2} + 2 x - 18 = - x

Move

x

to the left side

x^{2} + 3 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 18) = 9

x_{1, 2} = \frac{- 3 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 9}{2 \cdot 1}, x_{2} = \frac{- 3 - 9}{2 \cdot 1}

x = \frac{- 3 + 9}{2 \cdot 1} : 3

x = \frac{- 3 - 9}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 3, x = - 6

2 x^{2} - 378.4 x + 17856 = 0

2 x^{2} - x + 6

(2 x + 3)^{2} = 1

9 x^{2} = 11 + 6 x

x, 2 x^{2} h = 1000

What are the solutions to the equation x-3-(-x(x+1)+4)-5=(-x+6) ?
The solutions to the equation x-3-(-x(x+1)+4)-5=(-x+6) are x=3,x=-6
Find the zeros of x-3-(-x(x+1)+4)-5=(-x+6)
The zeros of x-3-(-x(x+1)+4)-5=(-x+6) are x=3,x=-6