What are the solutions to the equation r(r-1)+6r+6=0 ?

The solutions to the equation r(r-1)+6r+6=0 are r=-2,r=-3

Find the zeros of r(r-1)+6r+6=0

The zeros of r(r-1)+6r+6=0 are r=-2,r=-3

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r (r - 1) + 6 r + 6 = 0

r = - 2, r = - 3

Solution steps

r (r - 1) + 6 r + 6 = 0

Expand

r (r - 1) + 6 r + 6 : r^{2} + 5 r + 6

r^{2} + 5 r + 6 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 6 = 1

r_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 5 + 1}{2 \cdot 1}, r_{2} = \frac{- 5 - 1}{2 \cdot 1}

r = \frac{- 5 + 1}{2 \cdot 1} : - 2

r = \frac{- 5 - 1}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

r = - 2, r = - 3

640000 = 2 (2 x) (x) + 2 (2 x) (x) + 2 (2 x) (2 x)

0 = 3 x^{2} + 4 x - 15

18 a^{2} - 63 a + 10 = 0

8 x^{2} + 10 x = 3

x^{2} + 4 x - 1 = 7

What are the solutions to the equation r(r-1)+6r+6=0 ?
The solutions to the equation r(r-1)+6r+6=0 are r=-2,r=-3
Find the zeros of r(r-1)+6r+6=0
The zeros of r(r-1)+6r+6=0 are r=-2,r=-3