What are the solutions to the equation (16-2x)(9-2x)=78 ?

The solutions to the equation (16-2x)(9-2x)=78 are x=11,x= 3/2

Find the zeros of (16-2x)(9-2x)=78

The zeros of (16-2x)(9-2x)=78 are x=11,x= 3/2

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(16 - 2 x) (9 - 2 x) = 78

x = 11, x = \frac{3}{2}

Decimal Notation

x = 11, x = 1.5

Solution steps

(16 - 2 x) (9 - 2 x) = 78

Expand

(16 - 2 x) (9 - 2 x) : 144 - 50 x + 4 x^{2}

144 - 50 x + 4 x^{2} = 78

Move

78

to the left side

4 x^{2} - 50 x + 66 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 50 ) \pm ( - 50 ) ^{2} - 4 \cdot 4 \cdot 66}{2 \cdot 4}

(- 50)^{2} - 4 \cdot 4 \cdot 66 = 38

x_{1, 2} = \frac{- ( - 50 ) \pm 38}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 50 ) + 38}{2 \cdot 4}, x_{2} = \frac{- ( - 50 ) - 38}{2 \cdot 4}

x = \frac{- ( - 50 ) + 38}{2 \cdot 4} : 11

x = \frac{- ( - 50 ) - 38}{2 \cdot 4} : \frac{3}{2}

The solutions to the quadratic equation are:

x = 11, x = \frac{3}{2}

x^{2} + m = (m + 1) x - 1

0 = x^{2} + 5 x + 2

30625000 - 336875 x + 612.5 x^{2} = 0

2 m^{2} - 6 m - 8 = 0

x, \frac{x ^{2}}{q} + \frac{y ^{2}}{4} = 1

What are the solutions to the equation (16-2x)(9-2x)=78 ?
The solutions to the equation (16-2x)(9-2x)=78 are x=11,x= 3/2
Find the zeros of (16-2x)(9-2x)=78
The zeros of (16-2x)(9-2x)=78 are x=11,x= 3/2