What are the solutions to the equation (5sqrt(2))^2=1^2+x^2 ?

The solutions to the equation (5sqrt(2))^2=1^2+x^2 are x=7,x=-7

Find the zeros of (5sqrt(2))^2=1^2+x^2

The zeros of (5sqrt(2))^2=1^2+x^2 are x=7,x=-7

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(52)^{2} = 1^{2} + x^{2}

x = 7, x = - 7

Solution steps

(52)^{2} = 1^{2} + x^{2}

Expand

(52)^{2} : 50

Expand

1^{2} + x^{2} : 1 + x^{2}

50 = 1 + x^{2}

Switch sides

1 + x^{2} = 50

Move

1

to the right side

x^{2} = 49

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 49, x = - 49

49 = 7

- 49 = - 7

x = 7, x = - 7

x^{2} + 15 x + 21 = 0

(300 + 10 x) (1.6 - 0.1 x)

(3 x - 2) (2 x + 1) = 0

s^{2} + 3 s - 10 = 0

x^{2} - a x - b x + ab = 0

What are the solutions to the equation (5sqrt(2))^2=1^2+x^2 ?
The solutions to the equation (5sqrt(2))^2=1^2+x^2 are x=7,x=-7
Find the zeros of (5sqrt(2))^2=1^2+x^2
The zeros of (5sqrt(2))^2=1^2+x^2 are x=7,x=-7