What are the solutions to the equation x^2+15x+21=0 ?

The solutions to the equation x^2+15x+21=0 are x=(-15+sqrt(141))/2 ,x=(-15-sqrt(141))/2

Find the zeros of x^2+15x+21=0

The zeros of x^2+15x+21=0 are x=(-15+sqrt(141))/2 ,x=(-15-sqrt(141))/2

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x^{2} + 15 x + 21 = 0

x = \frac{- 15 + 141}{2}, x = \frac{- 15 - 141}{2}

Decimal Notation

x = - 1.56282 \dots, x = - 13.43717 \dots

Solution steps

x^{2} + 15 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot 21 = 141

x_{1, 2} = \frac{- 15 \pm 141}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 15 + 141}{2 \cdot 1}, x_{2} = \frac{- 15 - 141}{2 \cdot 1}

x = \frac{- 15 + 141}{2 \cdot 1} : \frac{- 15 + 141}{2}

x = \frac{- 15 - 141}{2 \cdot 1} : \frac{- 15 - 141}{2}

The solutions to the quadratic equation are:

x = \frac{- 15 + 141}{2}, x = \frac{- 15 - 141}{2}

(300 + 10 x) (1.6 - 0.1 x)

(3 x - 2) (2 x + 1) = 0

s^{2} + 3 s - 10 = 0

x^{2} - a x - b x + ab = 0

- 2 x^{2} = - 512

What are the solutions to the equation x^2+15x+21=0 ?
The solutions to the equation x^2+15x+21=0 are x=(-15+sqrt(141))/2 ,x=(-15-sqrt(141))/2
Find the zeros of x^2+15x+21=0
The zeros of x^2+15x+21=0 are x=(-15+sqrt(141))/2 ,x=(-15-sqrt(141))/2