What are the solutions to the equation 3m^2-2=7 ?

The solutions to the equation 3m^2-2=7 are m=sqrt(3),m=-sqrt(3)

Find the zeros of 3m^2-2=7

The zeros of 3m^2-2=7 are m=sqrt(3),m=-sqrt(3)

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3 m^{2} - 2 = 7

m = 3, m = - 3

Decimal Notation

m = 1.73205 \dots, m = - 1.73205 \dots

Solution steps

3 m^{2} - 2 = 7

Move

2

to the right side

3 m^{2} = 9

Divide both sides by

3

m^{2} = 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = 3, m = - 3

y^{2} - 6 y + 1 = - y^{2} + 2 y + 1

0 = x^{2} + 10 x

x^{2} + (\frac{48}{7})^{2} = 1

x, 3 x^{2} - 2 x y + 3 y^{2} - 4 x - 4 y - 12 = 0

x^{2} - 4 x - 160 = 0

What are the solutions to the equation 3m^2-2=7 ?
The solutions to the equation 3m^2-2=7 are m=sqrt(3),m=-sqrt(3)
Find the zeros of 3m^2-2=7
The zeros of 3m^2-2=7 are m=sqrt(3),m=-sqrt(3)