What are the solutions to the equation (2x-3)(1-x)=0 ?

The solutions to the equation (2x-3)(1-x)=0 are x= 3/2 ,x=1

Find the zeros of (2x-3)(1-x)=0

The zeros of (2x-3)(1-x)=0 are x= 3/2 ,x=1

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(2 x - 3) (1 - x) = 0

x = \frac{3}{2}, x = 1

Decimal

x = 1.5, x = 1

Solution steps

(2 x - 3) (1 - x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 3 = 0 or 1 - x = 0

Solve

2 x - 3 = 0 : x = \frac{3}{2}

Solve

1 - x = 0 : x = 1

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = 1

d^{2} + 4 d + 24 = 14 d + 24

x^{2} - 28 x + 132 = 0

900 x^{2} + 9998 x + 24330 = 4925.67 (3)

a^{2} - 28 a - 480 = 0

\frac{2}{3} x^{2} - 16 = 32

What are the solutions to the equation (2x-3)(1-x)=0 ?
The solutions to the equation (2x-3)(1-x)=0 are x= 3/2 ,x=1
Find the zeros of (2x-3)(1-x)=0
The zeros of (2x-3)(1-x)=0 are x= 3/2 ,x=1