What are the solutions to the equation -4x^2-16x-19=0 ?

The solutions to the equation -4x^2-16x-19=0 are x=-2-i(sqrt(3))/2 ,x=-2+i(sqrt(3))/2

Find the zeros of -4x^2-16x-19=0

The zeros of -4x^2-16x-19=0 are x=-2-i(sqrt(3))/2 ,x=-2+i(sqrt(3))/2

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- 4 x^{2} - 16 x - 19 = 0

x = - 2 - i \frac{3}{2}, x = - 2 + i \frac{3}{2}

Solution steps

- 4 x^{2} - 16 x - 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 ( - 4 ) ( - 19 )}{2 ( - 4 )}

Simplify

(- 16)^{2} - 4 (- 4) (- 19) : 43 i

x_{1, 2} = \frac{- ( - 16 ) \pm 4 3 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 3 i}{2 ( - 4 )}, x_{2} = \frac{- ( - 16 ) - 4 3 i}{2 ( - 4 )}

x = \frac{- ( - 16 ) + 4 3 i}{2 ( - 4 )} : - 2 - i \frac{3}{2}

x = \frac{- ( - 16 ) - 4 3 i}{2 ( - 4 )} : - 2 + i \frac{3}{2}

The solutions to the quadratic equation are:

x = - 2 - i \frac{3}{2}, x = - 2 + i \frac{3}{2}

y, x = 9 - y^{2}

t, h = - 16 t^{2} + 50

12 x^{2} + 12 = 25 x

n (t) = - 2.82 t^{2} + 25.74 t + 60.87

(x - 6) (x - 8) = 7 (x - 1) (x + 8) + x^{2}

What are the solutions to the equation -4x^2-16x-19=0 ?
The solutions to the equation -4x^2-16x-19=0 are x=-2-i(sqrt(3))/2 ,x=-2+i(sqrt(3))/2
Find the zeros of -4x^2-16x-19=0
The zeros of -4x^2-16x-19=0 are x=-2-i(sqrt(3))/2 ,x=-2+i(sqrt(3))/2