What are the solutions to the equation 3x^2+4x=-1 ?

The solutions to the equation 3x^2+4x=-1 are x=-1/3 ,x=-1

Find the zeros of 3x^2+4x=-1

The zeros of 3x^2+4x=-1 are x=-1/3 ,x=-1

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3 x^{2} + 4 x = - 1

x = - \frac{1}{3}, x = - 1

Decimal Notation

x = - 0.33333 \dots, x = - 1

Solution steps

3 x^{2} + 4 x = - 1

Move

1

to the left side

3 x^{2} + 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 \cdot 1}{2 \cdot 3}

4^{2} - 4 \cdot 3 \cdot 1 = 2

x_{1, 2} = \frac{- 4 \pm 2}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 4 + 2}{2 \cdot 3}, x_{2} = \frac{- 4 - 2}{2 \cdot 3}

x = \frac{- 4 + 2}{2 \cdot 3} : - \frac{1}{3}

x = \frac{- 4 - 2}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - 1

- 6 x^{2} + 2 = 0

3 x^{2} + x - 102 = 0

1 - x^{2}

x^{2} - 2 x + 50

x^{2} - 2 x + 13

What are the solutions to the equation 3x^2+4x=-1 ?
The solutions to the equation 3x^2+4x=-1 are x=-1/3 ,x=-1
Find the zeros of 3x^2+4x=-1
The zeros of 3x^2+4x=-1 are x=-1/3 ,x=-1