What are the solutions to the equation 80=14x^2 ?

The solutions to the equation 80=14x^2 are x=(2sqrt(10))/(sqrt(7)),x=-(2sqrt(10))/(sqrt(7))

Find the zeros of 80=14x^2

The zeros of 80=14x^2 are x=(2sqrt(10))/(sqrt(7)),x=-(2sqrt(10))/(sqrt(7))

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80 = 14 x^{2}

x = \frac{2 10}{7}, x = - \frac{2 10}{7}

Decimal Notation

x = 2.39045 \dots, x = - 2.39045 \dots

Solution steps

80 = 14 x^{2}

Switch sides

14 x^{2} = 80

Divide both sides by

14

x^{2} = \frac{40}{7}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{40}{7}, x = - \frac{40}{7}

\frac{40}{7} = \frac{2 10}{7}

- \frac{40}{7} = - \frac{2 10}{7}

x = \frac{2 10}{7}, x = - \frac{2 10}{7}

3 m^{2} + 30 m - 27 = 6

2^{2} + x^{2} = 6^{2}

x, f (a + 1) = 2 x^{2} - x + 4

184 = 9 + 7 x^{2}

3 f (b) = x^{2} - 1

What are the solutions to the equation 80=14x^2 ?
The solutions to the equation 80=14x^2 are x=(2sqrt(10))/(sqrt(7)),x=-(2sqrt(10))/(sqrt(7))
Find the zeros of 80=14x^2
The zeros of 80=14x^2 are x=(2sqrt(10))/(sqrt(7)),x=-(2sqrt(10))/(sqrt(7))