What are the solutions to the equation 3f(b)=x^2-1 ?

The solutions to the equation 3f(b)=x^2-1 are x=sqrt(3f(b)+1),x=-sqrt(3f(b)+1)

Find the zeros of 3f(b)=x^2-1

The zeros of 3f(b)=x^2-1 are x=sqrt(3f(b)+1),x=-sqrt(3f(b)+1)

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3 f (b) = x^{2} - 1

x = 3 f (b) + 1, x = - 3 f (b) + 1

Solution steps

3 f (b) = x^{2} - 1

Switch sides

x^{2} - 1 = 3 f (b)

Move

1

to the right side

x^{2} = 3 f (b) + 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 3 f (b) + 1, x = - 3 f (b) + 1

\frac{1}{7} y^{2} = \frac{3}{7} y

- x = x - x^{2}

2 - 2 k^{2} = 0

x = x (3 - x)

x = a (1 - \frac{z ^{2}}{b ^{2}}), z

What are the solutions to the equation 3f(b)=x^2-1 ?
The solutions to the equation 3f(b)=x^2-1 are x=sqrt(3f(b)+1),x=-sqrt(3f(b)+1)
Find the zeros of 3f(b)=x^2-1
The zeros of 3f(b)=x^2-1 are x=sqrt(3f(b)+1),x=-sqrt(3f(b)+1)