What are the solutions to the equation 1/3 pir^2(3)=25pi ?

The solutions to the equation 1/3 pir^2(3)=25pi are r=-5,r=5

Find the zeros of 1/3 pir^2(3)=25pi

The zeros of 1/3 pir^2(3)=25pi are r=-5,r=5

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\frac{1}{3} π r^{2} (3) = 25 π

r = - 5, r = 5

Solution steps

\frac{1}{3} π r^{2} (3) = 25 π

Move

25 π

to the left side

\frac{1}{3} π r^{2} \cdot 3 - 25 π = 0

Factor

\frac{1}{3} π r^{2} \cdot 3 - 25 π : π (r + 5) (r - 5)

π (r + 5) (r - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

r + 5 = 0 or r - 5 = 0

Solve

r + 5 = 0 : r = - 5

Solve

r - 5 = 0 : r = 5

The solutions to the quadratic equation are:

r = - 5, r = 5

x, 4 (y - 2 x + 3) = (x + c)^{2}

x^{2} + (- \frac{2}{2})^{2} = 1

(2 p + 3)^{2} = p^{2} - 5 p + 9

450 x - 5 x^{2} = 0

3 x^{2} - 8 x - 30 = 0

What are the solutions to the equation 1/3 pir^2(3)=25pi ?
The solutions to the equation 1/3 pir^2(3)=25pi are r=-5,r=5
Find the zeros of 1/3 pir^2(3)=25pi
The zeros of 1/3 pir^2(3)=25pi are r=-5,r=5