What are the solutions to the equation 16a^2-25=0 ?

The solutions to the equation 16a^2-25=0 are a= 5/4 ,a=-5/4

Find the zeros of 16a^2-25=0

The zeros of 16a^2-25=0 are a= 5/4 ,a=-5/4

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16 a^{2} - 25 = 0

a = \frac{5}{4}, a = - \frac{5}{4}

Decimal Notation

a = 1.25, a = - 1.25

Solution steps

16 a^{2} - 25 = 0

Move

25

to the right side

16 a^{2} = 25

Divide both sides by

16

a^{2} = \frac{25}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = \frac{25}{16}, a = - \frac{25}{16}

\frac{25}{16} = \frac{5}{4}

- \frac{25}{16} = - \frac{5}{4}

a = \frac{5}{4}, a = - \frac{5}{4}

x, p x^{2} - p (p + 3) x + 2 p (p + 1) = 0

x, y = x^{2} + 4 x + 9

x, h = - \frac{x}{2} (x - r) + 2

a x^{2} = 2 x + 6

64 + b^{2} = 289

What are the solutions to the equation 16a^2-25=0 ?
The solutions to the equation 16a^2-25=0 are a= 5/4 ,a=-5/4
Find the zeros of 16a^2-25=0
The zeros of 16a^2-25=0 are a= 5/4 ,a=-5/4